Question

3. A store has 9 employees, five of whom are males and four are females i.e. (M1, M2, M3, M4, M5, F1, F2, F3, F4). The store manager has to select three employees at random for further training. (a) In how many ways the manager can do this? (b) If all choices are equally possible, find the probability that at Least one female employee is selected for the training

Answer 1

Given, there are 9 employees in a store (5 male and 4 female) Three employees at random has to be selected for training a) Total number of ways the manager can select 3 out of 9 9C3 84 b) At least one female should be selected Plone female) + P(2 females) + P(3 females)--RO2+ 4c2'ngt-c3Ч 40+30+4 0.8809 84