A technology company has 70 employees, 38 males and 32 females. Assume that the manager of the company will promote 9 employees randomly this year. What is the probability that at least 2 female employees will be promoted?
We need to find the probability that out of 9 employees, at least two female employees are promoted.
Now let F be the event of a female employee being promoted.
Then we have
with the following probability distribution:
x | P(X=x) |
0 | 0.004094 |
1 | 0.03103 |
2 | 0.104521 |
3 | 0.205375 |
4 | 0.259422 |
5 | 0.21846 |
6 | 0.122644 |
7 | 0.044263 |
8 | 0.009318 |
9 | 0.000872 |
Now we need to find
Hence the required probability is 96.4876%
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A technology company has 70 employees, 38 males and 32 females. Assume that the manager of...
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