Question

E = 180 GPa and I = 65.0(106) mm. 10 KN 3 kN/m -3 m Part A Determine the slope of end A of the cantilevered beam. Express your answer to three significant figures and include the appropriate units. H ? 5.10-5

Answer 1

E=180 GP qz (180x1000) mpa I = 65 X 106 mm 14 10 KN=10,000N 3000 FT 3 KN mnm mmmmte B boomine А A MB RB RB and MB Calculating Evertical force to -- JO900 - 3000 x 3) +RB=0 RB = 19000 N Calculating MBT (-10,000*3)-(3000X 3 *2)= .) = Me 4 3500 Nm MB 10)

X 10,000 3000 N/m abortimonen D 43500, -190001 X Cut section x-x at a distance x from B Mx-x = (19000.*)-(43500)- 3000.X Mx-1 x-8 = 19000 - 43500 -1500 x2 2 Now we know EIdy X-X dx² dx? Eid = 19000 x – 43500 – 1500 x 2 Integrating with Respect to se Eldy 19000942 43500.40-150023 +G 3 2 ar

Now at X=0 => dy dx = 1.9000 (092 - 43 500(0)- 15001093 2 3 tci sta EI dy dx 9.500 – 43500X -500x3

slope at A that is at x= 3 m EI dy 950o (3)2 43500 (3) dx 5oo (3) EI dy -58 500. 3 2 dx Now E=180 G Pa = (180x108) pa 65x10 6xlo- I = 658106 mm4 ina put in a 180x109 x65x106x10-2) dy-58500 dx dy oooos radian dx slope at A i;e at x: 3m from Cantilever.