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+ Hooke's Law expresses the restoring force of an ideal spring in terms of its spring...
To understand the use of Hooke's law for a spring. Hooke's law states that the restoring...
To understand the use of Hooke's law for a spring. Hooke's law states that the restoring force F⃗ on a spring when it has been stretched or compressed is proportional to the displacement x⃗ of the spring from its equilibrium position. The equilibrium position is the position at which the spring is neither stretched nor compressed. Recall that F⃗ ∝x⃗ means that F⃗ is equal to a constant times x⃗ . For a spring, the proportionality constant is called the spring constant and denoted...
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring...
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring's restoring force is opposite the stretch direction. You have a plot from weight IN] versus stretch [m). The data forms a linear trend y 3.662x+1,67. How much will the spring stretch if 51.7 grams is hung on the spring? Answer in centimeters with three significant figures or N/A if not enough information...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax-...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax- 2 N if it stretched or compressed, where α = 60 N/m and β 18.0 Nm2/3. The mass of the spring is negligible. (a) Calculate the work function W(x) for the spring. Let U=0 when x=0. (b) An object of mass 0.900 kg on a horizontal surface is attached to this spring. The surface provides a friction force that is dependent on distance Fr(x)2x2...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs....
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs. According to Hooke's law, the force required to compress or stretch a spring from an equilibrium position is given by F(x) = kx, for some constant k. The value of k (measured in force units per unit length) depends on the physical characteristics of the spring. The constant k is called the spring constant and is always positive. Part 1. Suppose that it takes...
Suppose a force of 40 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is req...
Suppose a force of 40 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position? c. How much work is required to stretch the spring 0.5 m from its equilibrium position? d. How much additional work is required to stretch the spring 0.1 m if it has...
Table 1: Experimental data for Hooke's Law lab. Mass (kg) Force (N) Ax (m) 0.100 0.100(9.8)=...
Table 1: Experimental data for Hooke's Law lab. Mass (kg) Force (N) Ax (m) 0.100 0.100(9.8)= 0.98 N 0.017 0.139 0.139(9.8)= 1.362 N 0.023 0.165 0.165(9.8)= 1.617 N 0.028 0.090 0.09(9.8)= 0.882 N 0.015 0.300 0.300(9.8)= 2.94 N 0.050 0.050 0.050(9.8)= 0.49 N 0.009 Part B: Determining Unknown Mass Now that you have your spring constant, we are going to determine unknown masses. For the red and blue masses in the simulation, perform experiments to determine their mass. Show your...
2. Consider the following physical situation: A spring that obeys Hooke's Law and has a known/given spring constant k has been compressed to half of its equilibrium length. It's anchored at o...
2. Consider the following physical situation: A spring that obeys Hooke's Law and has a known/given spring constant k has been compressed to half of its equilibrium length. It's anchored at one end while the other end pushes (but is not attached to) a block of mass m in the horizontal direction. The block is initially held in place. Once released, the block accelerates to the right and achieves a final speed of ve at the point when it leaves...
please answer all prelab questions, 1-4. This is the prelab manual, just in case you need...
please answer all prelab questions, 1-4.
This is the prelab manual, just in case you need background
information to answer the questions. The prelab questions are in
the 3rd photo.
this where we put in the answers, just to give you an
idea.
Lab Manual Lab 9: Simple Harmonic Oscillation Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and...
s Law for this (F--ks): Where F is the spring's restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring's restoring force is opposite the stretch direction. You have a plot from weight IN] versus stretch [m). The data forms a linear trend y 3.662x+1,67. How much will the spring stretch if 51.7 grams is hung on the spring? Answer in centimeters with three significant figures or N/A if not enough information...
A spring is found to not obey Hooke's law. It exerts a restoring force F(x) =-ax- 2 N if it stretched or compressed, where α = 60 N/m and β 18.0 Nm2/3. The mass of the spring is negligible. (a) Calculate the work function W(x) for the spring. Let U=0 when x=0. (b) An object of mass 0.900 kg on a horizontal surface is attached to this spring. The surface provides a friction force that is dependent on distance Fr(x)2x2...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAX, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 103 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
1. According to Hooke's law, the force exerted by a spring is proportional to the amount of stretch (or change in length Ax) and is given by F = -KAx, where the minus sign indicates it is a restoring force. If a force of 120 N acts on a mass 250 g attached to a spring of constant K = 54.55 x 10 N/m. Calculate the following: The change in length Ax The angular frequency (w) The frequency (f) The...
(1 point) Finding the work done in stretching or compressing a spring. Hooke's Law for Springs. According to Hooke's law, the force required to compress or stretch a spring from an equilibrium position is given by F(x) = kx, for some constant k. The value of k (measured in force units per unit length) depends on the physical characteristics of the spring. The constant k is called the spring constant and is always positive. Part 1. Suppose that it takes...
Suppose a force of 40 N is required to stretch and hold a spring 0.1 m from its equilibrium position. a. Assuming the spring obeys Hooke's law, find the spring constant k. b. How much work is required to compress the spring 0.2 m from its equilibrium position? c. How much work is required to stretch the spring 0.5 m from its equilibrium position? d. How much additional work is required to stretch the spring 0.1 m if it has...
Table 1: Experimental data for Hooke's Law lab. Mass (kg) Force (N) Ax (m) 0.100 0.100(9.8)= 0.98 N 0.017 0.139 0.139(9.8)= 1.362 N 0.023 0.165 0.165(9.8)= 1.617 N 0.028 0.090 0.09(9.8)= 0.882 N 0.015 0.300 0.300(9.8)= 2.94 N 0.050 0.050 0.050(9.8)= 0.49 N 0.009 Part B: Determining Unknown Mass Now that you have your spring constant, we are going to determine unknown masses. For the red and blue masses in the simulation, perform experiments to determine their mass. Show your...
2. Consider the following physical situation: A spring that obeys Hooke's Law and has a known/given spring constant k has been compressed to half of its equilibrium length. It's anchored at one end while the other end pushes (but is not attached to) a block of mass m in the horizontal direction. The block is initially held in place. Once released, the block accelerates to the right and achieves a final speed of ve at the point when it leaves...
please answer all prelab questions, 1-4.
This is the prelab manual, just in case you need background
information to answer the questions. The prelab questions are in
the 3rd photo.
this where we put in the answers, just to give you an
idea.
Lab Manual Lab 9: Simple Harmonic Oscillation Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and...
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