According to Gauss' Law,
you will get the same answer no matter where the charge q is
placed inside the box, and no matter how large the box is. It does
not even have to be a cube, as long as it encloses the
charge.
Total flux = q/(epsilon-zero)
= 1.8*10^-6/8.82*10^-12
= 2.04*10^5 (N*m^2/C)
That is a lot easier than doing the actual integration of E(normal)
over the six sides of the cube, but the answer will be the
same.
Question 5 Whay the ans is not zero scince it is aclosed surface the net electric...
A point charge of 1.8μC at the center of a cubical Gaussian surface 55 cm on edge. What is the net electric flux through the surface?
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