Question

Calculate the total and average binding energies and the packing fraction for (126)C. E/A (MeV) BINDING ENERGY PER NUCLEON AS A FUNCTION OF MASS NUMBER 40 60 80 100 120 140 160 180 200 220 240 Mass number

Answer 1

Solution :- The generral from of representing a Particular nu clear reaction is jiven by (^ =)x = z (* 2) H + ( A – 2) (' 0)n Symbol cor reponding to Where X = elemental Cchemical the value of %, number 1 : atomic A : Protons + neutons = mass number the reaction is consequently, for (12 6) C (12 6)c =6(' ) H + 6 (' o) n. %3D is For a nucleus, the auerrage binding ene defined as the total binding eneryy Value of A. The total binding enengy. divided the by is the Energy for reaction 0) as calculated from the difference in the rest masses of pratucts and reactants. Therefore, the average binding energy for reaction (2) is grven by [[A (mass) }/12] = [T6(1- 007825) +6(1.008665) - 12.0005 [ro.098940 M)/(1a)) 2.000000F IM : 1 amu, AE = (Am) Where c is the speed of light. Therefore, amu'x (2.997925 (100) [t0.09894 amu x |-6605 (103g amu'x(.997925 (10") amu x l.6605 (10)9 " cm see')'

X 10 Jsec 3/ {1.6022(10")J ev'x1o'ev Mev's] = 92.163 Mev. The packing fraction ts given by * I/AJ Pf =[{ (M-A) 10 Where Pf - packing fraction. M-A - mass excess less the number, a result %3D mass of the nuclide in In this Problem observe that M- A. AS equetion (3) yfelds %3D Pf = [[(12-12) 10t /(12)) Pf : 0.