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Assignment Score: 81.5% Resources [ Give Up? Hint Check Answer KA TY Question 16 of 17 > Suppose Gabe, an elementary school s

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Judy can return at any time in 50 seconds after she exits the room. The probability of her returning at any time is the same.

Now, Gabe does not do anything apart from wondering for the first 10 seconds after Judy steps out of the room. And Gabe takes 20 seconds to grab a cookie and devour it with no trace. Now, for Judy to catch Gabe, she should return back within these 20 seconds.

Hence, the probability of Gabe being caught is the same as the probability that Judy returns back within the 20 seconds that Gabe is stealing and devouring the cookie.

Let T be the random variable that describes the time taken by Judy to return back. Since the probability of her returning is the same between the time interval a = 0 seconds and b = 50 seconds, T follows a uniform distribution U(a, b) = U(0, 50).

For uniform distribution, the pdf is given as:

f(x) = \frac{1}{b- a}

Substituting the values, we have:

f(t) = \frac{1}{50 - 0} = \frac{1}{50}

Now, the time between which Gabe can be caught is 10 and 30 seconds. Hence, we are to determine the probability that T lies in the interval 10 and 30 seconds.

Pr(10\leq T\leq 30)

This is given as:

\\Pr(10\leq T\leq 30) = (30 - 10)\times \frac{1}{50}\\\\ \therefore Pr(10\leq T\leq 30) = 20\times \frac{1}{50}\\\\ \therefore Pr(10\leq T\leq 30) = 0.4

Hence, the probability of Gabe being caught is 0.40.

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