Question

2. (a) Prove that the following sequents cannot be valid: (i) ( PQ) V ~RE (~Q ^ R) P (ii) PQ, R=~SE (PVR) = (Q V S)

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Answer #1

(i) P => Q is equivalent to ~P V Q

Therefore the expression ( P => Q ) V ~ R becomes ~P V Q V ~ R

Now ( ~ Q /\ R ) => P is equivalent to ~ ( ~Q /\ R ) V P

which is equivalent to Q V ~ R V P ( Demorgans law ) i.e P V Q V ~R ( Rearranging )

Therefore our sequent becomes

~P V Q V ~ R ⊢  P V Q V ~R

Truth table for ~P V Q V ~R

(TP v (QVER)) O E F F F LEE ELE LEE EEEE ELLE

Truth Table for  P V Q V ~R

P F Q R R (P v (Q v R)) F F T FI F F F TF T F TT T T F F T T T FT TF T T T T T T

From the truth table values it is clear that  P V Q V ~R is not provable from ~P V Q V ~ R. The sequent is not valid

(ii) Given P => Q

Therefore ~P V Q

Now R=> ~S is equivalent to ~R V ~S

combining these two conditions, we have

(~P V Q ) /\ ( ~R V ~ S)

Truth table for (~P V Q ) /\ ( ~R V ~ S) is as follows

P Q R S ((PvQ) A (RV -S)) T F F חד F F חד F T T F F T F T F F T T F F T. חד F T F T F T T F T T F T F T T T F T F F F T F חד

Now ( P V R ) => ( Q V S ) is equivalent to ~ ( P V R ) V (Q V S )

i.e ~P /\ ~ R V Q V S

Truth table for ~ P /\ ~ R V Q V S is as follows

Р Q R S ((PAR) v (Q v S)) F F F T F F F F T T F F F F T T F F T T F T F F T F T F T T F T T F T F T T T T T F F F F T F F T T

From the truth table values it is clear that  ~ P /\ ~ R V Q V S is not provable from (~P V Q ) /\ ( ~R V ~ S).

Hence sequent is not valid.

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