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25. When calculating the power of a pure resistive load, the voltage and current are in power factor is a. one b. two c. thre
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Answer #1

25.

Power= Voltage* current* power factor

power factor=cos(angle)

for pure resistive load power factor=1

therefore,

Power=V*I

Bonus question:

given data:

Ep=120V= Volatge on primary side

Es=500V=Volatge on secondary side

Ns=800= Number of turns on secondary side

Np=Number of turns on primary side

Zs=1200 Ohms=Impedance on secondary side

Camlin Date 1 Wkt Ep = Np = Is ES Ns Ip. 0 : Ep = NP LS NS ie, 120 = Np 500 900 . Np: 120 x 800 Np = 192 turns 500Wkt V=It gu. 25 = 12002 . Es = Ists 500 = Is (1200) 19 = 500 = 0.41674 1200 Ep = Is from15 0.4167 = 120 ap 500 = 0.4167 X 500 120 Jp = 1.736A Surns ratio : Np = 192 = 0.24 800

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