A reaction has a standard free-energy change of -11.40 kJ mol-1(-2.725 kcal mol-1). Calculate the equilibrium constant for the reaction at 25°C.
A reaction has a standard free-energy change of –16.50 kJ mol-1(-3.944 kcal mol-1). Calculate the equilibrium constant for the reaction at 25 °C. Keq = _______
A reaction Alaq) + Blaq) = Claq) has a standard free-energy change of -3.44 kJ/mol at 25°C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? Number Number Number [A]= M [B] = [c]= 0 How would your answers above change if the reaction had a standard free-energy change of +3.44 kJ/mol? O O All concentrations would be lower. All...
A reaction has a standard free-energy change of-489 kJ/mol at 25 °C. What are the concentrations concentrations are 0.30 M, 0.40 M, and 0 M, respectively? of A, B, and C at equilibrium if, at the beginning of the reaction, their Number Number Number How would your answers above change if the reaction had a standard free-energy change of +4.89 kJ/mol? O There would be no change to the answers. O All concentrations would be higher. All concentrations would be...
A reaction A(aq) + B(aq) = C(aq) has a standard free-energy change of -3.06 kJ/mol at 25 °C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? How would your answers change if the reaction had a standard free-energy change of +3.06 kJ/mol? O There would be less A and B but more C. All concentrations would be higher. There...
A reaction A(aq) + B(aq) = C(aq) has a standard free-energy change of -3.38 kJ/mol at 25°C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and OM, respectively? [A] = [B] = 1C) = How would your answers change if the reaction had a standard free-energy change of +3.38 kJ/mol? There would be no change to the answers. O All concentrations would be...
Consider the reaction A+B = C, with a standard free-energy change of -33.7 kJ/mol. If A, B, and C are mixed at initial concentrations 230 mm, 430 mM and 99 mm, respectively, at 25°C, the reaction (as written) will: O the reaction is at equilibrium o absorb ~ 17.0 kJ/mol of energy upon reaching equilibrium O proceed in the reverse direction, to produce more A and B O release ~ 17.0 kJ/mol of energy upon reaching equilibrium O proceed forward,...
A reaction A (aq) + B(aq) C(aq) has a standard free-energy change of-5.16 kJ/mol at 25 degree C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and 0 M, respectively? How would your answers above change if the reaction had a standard free-energy change of +5.16 kJ/mol? There would be less A and B but more C. All concentrations would be lower. All...
A reactionA(aq) + B(aq) <==> C(aq)has a standard free-energy change of -5.13 KJ/mol at 25℃What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30M, 0.40M and 0 M respectively?
The standard free energy change, AGo, for the reaction C2H5OH(g) C2H4(g) + H20(g) is +8.25 kJ/mol at 25°C. Calculate Kp for the equilibrium.
The standard free energy of activation of a reaction A is 71.6 kJ mol–1 (17.1 kcal mol–1) at 298 K. Reaction B is one million times faster than reaction A at the same temperature. The products of each reaction are 10.0 kJ mol–1 (2.39 kcal mol–1) more stable than the reactants. (a) What is the standard free energy of activation of reaction B?