Question

A reaction A(aq) + B(aq) = C(aq) has a standard free-energy change of -3.38 kJ/mol at 25°C. What are the concentrations of A, B, and C at equilibrium if, at the beginning of the reaction, their concentrations are 0.30 M, 0.40 M, and OM, respectively? [A] = [B] = 1C) = How would your answers change if the reaction had a standard free-energy change of +3.38 kJ/mol? There would be no change to the answers. O All concentrations would be lower. There would be less A and B but more C. There would be more A and B but less C. O All concentrations would be higher.

Answer 1

Answer

Relation constant b/w Standard fee energy and aquilibrium AG = - RT luk Ecuilibrium constant -Stol- free energy - 3.38 x 103 J/mol 303 – – 8.314 It ma x 2.303 x log X 298k = log k X 2.303 +3.38 x 10 J/mol + 8,314 Jkt mot X 298K

- 0.592 = log k antilog (0.592) - K K = 3.908 Nasy constructing an Icetale for the equilibrium A ag & Bar - Class 0.30 0.40 0 given I +X - x 0.30-X -x 6.40-X +x

Units of A,B and C is M.

When standard free energy positive the reaction favours the reactants more than the products. So accordingly there will be more A and B and less C.