Question

Page 3 of 3 November 16, 2019 INEL 42013-1920-1 SEC (20) (40) Name III. (34 pts) The amplifier shown below is called a phase inverter. Given that the drain current lo = 250 A Determine the voltag 250 UA Determine the voltage gains (a) Vod/Vs and (b) Vos/Vs. 20V Parameters: K = (K' W/L)/2 = 15.63 A/v2, Vthn = 1V, ro = 00 Rd 3 R1 206 (a) Vod/Vs = 1 Meg Vod C1 (b) Vos/Vs = 10uF Vos R2 Rs W- 1 Meg

Answer 1

DC. ana ly sis: * all capacitas ale open coupling circited * AC sources are shost circuited .+20V 05 Meg TH I-OTI lov 20K -10V + IG (0.5 meg) + VG+ Ip (2012) -0. Var = 10 – 208250 x1ő 5 V cs Scanned with one Vol. CamScanher

Now, - 20 + 20% ras0M + Vo 70' Vo 2 ISV and Va & lov gines N-MOSFET in Saturs a tion Region rew [vo > VG VAN So, C (0) Acc analy sis : * All dic sources are shost ale circuited. open circuited. capacitor "U coupling od t I dok olles? v e Rille? 40k cs Scanned with CamScanner

Now, apply KvL at Loop (1) - Vs + Vgx + 3im Vox (206) 20 Vs = Vyk (1+9m 420k) and Vad - – Vg4* 9 *20% - (a) - (6) Here, we don't know the value of im we know that To + ) vau van)." po e ) .al ven, um Som 2015-63100 (5-1) 8*15.63 1106 cs Scangry with 0.125 malv CamScanner

from (0)4 (6) Vod -9m *204 x vik = (1+9m X205) Yeter A -01125x20 [140125420) 3.5 and Vos ? Som Vas 203 — C) from (a) +V+ Smx20k Vgs ( 1 + 379 *20k) 0.125 196 x20x063 ( + b^(-3317 rao nº) Ics Scanned with home 0.714 7 Scanned with v CamScann