Question

This is a fill in the code type:

// FILL IN THE CODE - Write a program to multiply 2 numbers, print out the results and print out the original numbers in ascending order.

#include <iostream>

using namespace std;

int main() {

  int num1;       // holds 1st number

  int num2;       // holds 2nd number

  int result;       // holds result of multiplication

  int *num1Ptr = nullptr; // int pointer which will be set to point to the 1st number

  int *num2Ptr = nullptr;     // int pointer which will be set to point to the 2nd number

  cout << "Please input the 1st number" << endl;

  cin >> num1;

  cout << "Please input the 2nd number" << endl;

  cin >> num2;

// Fill in code to make num1Ptr point to num1 (hold its address)

// Fill in code to make num2Ptr point to num2 (hold its address)

  num1Ptr = &num1;

  num2Ptr = &num2;

// Fill in code to find the result by using only the pointer variables

  result = *num1Ptr * *num2Ptr;

  cout << "The result is " << result << endl;

  if (*num1Ptr > *num2Ptr)

    cout << "The 1st number is greater than the 2nd number" << endl;

    

    else if (*num2Ptr > *num1Ptr)

    cout << "The 2nd number is greater than the 1st number" << endl;

    

    else

    cout << "The 2nd number and 1st number are the same" << endl;

  return 0;

}

I have filled out all the ones that needs to be filled.

It says "Write a program to multiply 2 numbers, print out the results and print out the original numbers in ascending order."

It's already printing out the results of the two numbers multiplied, but I'm not quite sure how to print put the original numbers in ascending order. Let's say, the user inputs 8 then 10. it should display 8, 10. Thank you.

Answer 1

#include <iostream>

using namespace std;

int main() {
    int num1;       // holds 1st number
    int num2;       // holds 2nd number
    int result;       // holds result of multiplication
    int *num1Ptr = nullptr; // int pointer which will be set to point to the 1st number
    int *num2Ptr = nullptr;     // int pointer which will be set to point to the 2nd number
    cout << "Please input the 1st number" << endl;
    cin >> num1;
    cout << "Please input the 2nd number" << endl;
    cin >> num2;
// Fill in code to make num1Ptr point to num1 (hold its address)
// Fill in code to make num2Ptr point to num2 (hold its address)
    num1Ptr = &num1;
    num2Ptr = &num2;
// Fill in code to find the result by using only the pointer variables
    result = *num1Ptr * *num2Ptr;
    cout << "The result is " << result << endl;
    if (*num1Ptr > *num2Ptr) {
        cout << "The 1st number is greater than the 2nd number" << endl;
        cout << "Numbers in ascending order is " << *num2Ptr << ", " << *num1Ptr << endl;
    }

    else if (*num2Ptr > *num1Ptr) {
        cout << "The 2nd number is greater than the 1st number" << endl;
        cout << "Numbers in ascending order is " << *num1Ptr << ", " << *num2Ptr << endl;
    }

    else {
        cout << "The 2nd number and 1st number are the same" << endl;
        cout << "Numbers in ascending order is " << *num2Ptr << ", " << *num1Ptr << endl;
    }
    return 0;
}