Question

4.3 Find the equation of a plane that passes through (1,-2,4), (2,4,-4), and (1.25,-0.5, 2) using cross products and normal vectors. To find the equation of the plane, pick a point not on the plane.

Answer 1

8) Let! poruts Je PC,-2,4); L2,h-h)(.25,-05,2) There could a uniqul thee be p lani through only ÿ 2 'ave three po it P,P&R at col linear points, 1 Now ) -0:5

dutirminant is P,a&R cellimear are points, ie all gn a the m les sirgle line- Thus, thre Le in pine'tely mang p lecnes th at Ahrou fr passes 3 pohts . these 9leuse check # data i's you v ques don correct not ht x Amn) lieg thad be Puint -the pleme (0-1) ?+ (m+2 ) ê +(n-4) (e-d PR = The Gm -4) 2 te the p kine -) nomal vec to v n-4 m+ 2 nth l-2 [0-) (m-) - (&2) (m*2] E +6n

uppah people in the field of Terracotta figurines and seals throw a liad practices followed hy the 2 knives PC),-2,4) A Plan puse) thicough equcth (Pm+Gn=8)(n -1) + (-s&-n+)Xy2)+(cd+m+16)X3-4)=0

Feel free to ask doubts in the comment section and give it a thumbs up if you liked the answer. Have a good day.