3. For a particle of mass m in a box of size a, the wavefunction is...
(15) 4. The state of the particle-in-a box located between 0<x<a is described by the following normalized wavefunction at t=0: Y(x,t=0) =(1/2) A Sin (fx/a)-(1/12) A Sin(3 rex/a) + (1/2) A Sin(5tx/a) (10) a) If the energy of the system is measured at t=0, what energies will be observed What is the probability (in percent) of observing an energy E> 9h-/8ma?? on
A particle with mass m is in a one dimensional simple harmonic oscillator potential. At timet0 it is described by the superposition state where Vo, 1 and Vz are normalised energy eigenfunctions of the harmonic oscillator potential corresponding to energies Eo, E1 and E2 (a) Show that the wavefunction is normalised (b) If an observation of energy is made, what is the most likely value of energy and with what probability would it be obtained? (c) If the experiment is...
3. A particle is in a 1D box (infinite potential well) of dimension, a, situated symmetrically about the origin of the x-axis. A measurement of energy is made and the particle is found to have the ground state energy: 2ma The walls of the box are expanded instantaneously, doubling the well width symmetrically about the origin, leaving the particle in the same state. a) Sketch the initial potential well making it symmetric about x - 0 (note this is different...
For the particle-in-a-box of length a, assume that instead of a sine function, the ground state wavefunction is an upside-down parabola at the center of the box, b/2. What is the total energy of the trial system and what is the wavefunction of the system. Now compare your result to the particle-in-a-box where the potential energy inside the box is zero, what is the difference of percentage of both systems? For the particle-in-a-box of length a, assume that instead of...
Quatum Mechanics Question 3. (a) A particle of mass m is stuck in a 2D box of length I i. What are the wavefunctions? ii. What are the energies of the ground state and first excited state? 3. (a) A particle of mass m is stuck in a 2D box of length I i. What are the wavefunctions? ii. What are the energies of the ground state and first excited state?
2.2 Two-level system A particle in the box is described by the following wavefunction 1 1 V(x, t) + V2 V2 = Um(x)e -i(Em/h) In other words, this state is a superposition of two modes: n-th, and m-th. A superposition that involves only two modes (not necessarily particle in the box modes, but any two modes) is called a "two-level system”. A more modern name for such a superposition is a "qubit”. a) Come up with an expression for the...
Questions 1 - 5 deal with a particle in a one-dimensional infinite square well of width a where 0, 0 SX Sa V(x) = 100, Otherwise. The stationary states are Pn(x) = sin(**) with energies En = "forn = 1,2,3.. Question 1 (14 pts) Which of the following is correct? A. The Hilbert space for this system is one dimensional. B. The energy eigenstates of the system form a ID Hilbert space. C. Both A and B are correct. D....
3.9. A particle of mass m is confined in the potential well 0 0<x < L oo elsewhere (a) At time t 0, the wave function for the particle is the one given in Problem 3.3. Calculate the probability that a measurement of the energy yields the value En, one of the allowed energies for a particle in the box. What are the numerical values for the probabilities of obtaining the ground-state energy E1 and the first-excited-state energy E2? Note:...
question 7 9 10 ), where n, a, and are constant, is an eigenfunction of p. 7. (a) p. =- what is p. ? (b) sin( i ax what is the eigenvalue? (107) (9) = v ydt for a normalized wavefunction. Please find (1) for(a) v. - and (b) 42p. 4/2008 re s in sind. (hint : integrate over all space: sin Odrdodø (sin? xdx = [l-c952de, 5 xede = (203) 3 2 10. A particle of mass m is...
P7D.6 Consider a particle of mass m confined to a one-dimensional box of length L and in a state with normalized wavefunction y,. (a) Without evaluating any integrals, explain why(- L/2. (b) Without evaluating any integrals, explain why (p)-0. (c) Derive an expression for ) (the necessary integrals will be found in the Resource section). (d) For a particle in a box the energy is given by En =n2h2 /8rnf and, because the potential energy is zero, all of this...