Homework Answers
Clausius clapeyron equation:
ln P1/P2 = deltaH /R * [ 1/T2 - 1/T1]
P1 = 1 atm
P2 = 92 atm (water will boil when atmospheric pressure = vapour pressure of water)
T2 = ?
T1 = 100 C = 373.15 K
delta H = 40.65 KJ/mol
R = 8.314
ln 1 / 92 = 40.65*1000 / 8.314 * [ 1 / T2 - 1/373.15]
T2 = 569.78 K = 297.78 C
if we go by formula
We can see from te figure that
92 atm = 92.92*10^5 Pa pressure is present -----> in around 300 C
So answer is 307 C
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