Model Hiero's ship lauch experimentally by placing the pivot at the 30 cm mark and hanging...
Model Hiero's ship lauch experimentally by placing the pivot at the 30 cm mark and hanging a 200 g mass at the one centimeter mark. Calculate the mass that you need to place at the 90 cm mark in order to balance the ship such that the net torque is zero. Record calculated mass below. Assume the hanger used to hold the 200 g mass is part of the ship.
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Model Hiero's ship lauch experimentally by placing the pivot at
the 30 cm mark and hanging...
Wednesday, April 10, 2019 ue and balance Torque and balance problems LAB193_07 A balance and torq...
Wednesday, April 10, 2019 ue and balance Torque and balance problems LAB193_07 A balance and torque experiment is conducted with a balanced ruler (that is, the pivot point is in the middle). Length of the ruler. 1 m Weight of the ruler. 3 N Mass 1: 245 g. This mass is placed at the 2-cm mark on the ruler Mass 2: 40 g. Where should this mass be placed to balance the ruler? Answer Check A balance and torque experiment...
the experimental part for this question is all answered there is only the last part where it says: Compute the net torque about 20 cm mark. Mass of the stick : 0.1383 kg Compu...
the experimental part for this question is all answered there is
only the last part where it says:
Compute the net torque about 20 cm
mark.
Mass of the stick : 0.1383 kg
Compute the net torque about the end of the stick.
please be sure to put detailed answer for both parts 1 and 2
thanks for the help!
Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick...
Period Date Name 39 Solitary Seesaw Purpose To identify the forces, lever arms, and torques for a system in rota...
Period Date Name 39 Solitary Seesaw Purpose To identify the forces, lever arms, and torques for a system in rotational 2 knife-edge lever clamps set of slotted masses 2 mass hangers fulcrum string or masking tape Gravity pulls on every part of an object. The average position of these pulls (the weight) is the center of gavity (CG) of the object. The sum of all these pulls is the weight of the object. The entire weight of the object is...
Just need help filling in the blanks! Thank you. Part 1: Three Levers In this part,...
Just need help filling in the blanks! Thank you.
Part 1: Three Levers In this part, you will set up a lever in three different configurations. First Lever The first is straightforward: set up the plastic ruler so that it pivots about its center. Apply two forces (resulting in two torques) to it as shown. Torque 1: Torque 2: Place a hanger (20 grams) in the first hole to the left of center and add 200 grams to it. Place...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
I am in a intro engineering physics and having issues with this classwork for our lab.... the val...
I am in a intro engineering physics and having issues
with this classwork for our lab.... the values are given in the
table.thank u
In this exercise, you will begin with a system that is not in equilibrium, predict the mag nitude and direction of a force necessary to place it in equilibrium. You will also use second graphical technique to reach the same conchusion. Measurements around the side of the table mark 360 degrees. We will set 0 degrees...
Experiment 2: Rotational KE and Moment of Inertia Data. Please help with Last Trial Experiment Il:...
Experiment 2: Rotational KE and Moment of Inertia Data. Please help
with Last Trial
Experiment Il: Rotational KE and Moment of Inertia Data Radius of step-pulley groove: r = _ 0.02 Rod: L = 0.25m Mw=_30 8 = 0.16 Average mass of brass weights: Mr = _50 Mass of falling body: M = 40 8 m 0000003 Wahl APE -m /s IR rad Diff % m g ΔΚΕ, g.m/s Bom rad/s rad/s 0.12.0024 .9408 0.05 .4 0.18 .0036 1.4112 0.10...
the question is in last picture. i provided the lab content... I need guidance. thank you....
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
i need help with my biology lab Length 1 km = 1,000 m 1m = .001...
i need help with my biology lab
Length 1 km = 1,000 m 1m = .001 km 1m = 100 cm 1 cm = .01 m Weight 1 kg = 1,000 1g-,001 kg 1g - 100 g 1 cg=.018 18 = 1,000 mg 1 mg = .001 g Volume 1 kL = 1,000 L 1L = .001 Ki 1L = 100 CL 1 cl = .01L 1 L = 1,000 mL 1 mL = .001 L 1 mm = .001...
i dont understand why the molecular weight i calculated (42.012 g/mol) for my unknown liquid (acetone)...
i dont understand why the molecular weight i calculated
(42.012 g/mol) for my unknown liquid (acetone) is less than the
actual molecular weight (58.08 g/mol). what errors could i have
made in my lab that would account for the difference.
Molecular Weight of a Volatile Liquid In this experiment, an amount of liquid more than sufficient to fill the flask when vaporized is placed in a flask of measured volume and mass. The flask is then heated in a boiling...
Wednesday, April 10, 2019 ue and balance Torque and balance problems LAB193_07 A balance and torque experiment is conducted with a balanced ruler (that is, the pivot point is in the middle). Length of the ruler. 1 m Weight of the ruler. 3 N Mass 1: 245 g. This mass is placed at the 2-cm mark on the ruler Mass 2: 40 g. Where should this mass be placed to balance the ruler? Answer Check A balance and torque experiment...
the experimental part for this question is all answered there is
only the last part where it says:
Compute the net torque about 20 cm
mark.
Mass of the stick : 0.1383 kg
Compute the net torque about the end of the stick.
please be sure to put detailed answer for both parts 1 and 2
thanks for the help!
Q1) Torques and equilibrium Part A: use the following methods to find the center of mass for a measuring stick...
Period Date Name 39 Solitary Seesaw Purpose To identify the forces, lever arms, and torques for a system in rotational 2 knife-edge lever clamps set of slotted masses 2 mass hangers fulcrum string or masking tape Gravity pulls on every part of an object. The average position of these pulls (the weight) is the center of gavity (CG) of the object. The sum of all these pulls is the weight of the object. The entire weight of the object is...
Just need help filling in the blanks! Thank you.
Part 1: Three Levers In this part, you will set up a lever in three different configurations. First Lever The first is straightforward: set up the plastic ruler so that it pivots about its center. Apply two forces (resulting in two torques) to it as shown. Torque 1: Torque 2: Place a hanger (20 grams) in the first hole to the left of center and add 200 grams to it. Place...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
I am in a intro engineering physics and having issues
with this classwork for our lab.... the values are given in the
table.thank u
In this exercise, you will begin with a system that is not in equilibrium, predict the mag nitude and direction of a force necessary to place it in equilibrium. You will also use second graphical technique to reach the same conchusion. Measurements around the side of the table mark 360 degrees. We will set 0 degrees...
Experiment 2: Rotational KE and Moment of Inertia Data. Please help
with Last Trial
Experiment Il: Rotational KE and Moment of Inertia Data Radius of step-pulley groove: r = _ 0.02 Rod: L = 0.25m Mw=_30 8 = 0.16 Average mass of brass weights: Mr = _50 Mass of falling body: M = 40 8 m 0000003 Wahl APE -m /s IR rad Diff % m g ΔΚΕ, g.m/s Bom rad/s rad/s 0.12.0024 .9408 0.05 .4 0.18 .0036 1.4112 0.10...
the question is in last picture. i provided the lab content...
I need guidance. thank you.
INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...
i need help with my biology lab
Length 1 km = 1,000 m 1m = .001 km 1m = 100 cm 1 cm = .01 m Weight 1 kg = 1,000 1g-,001 kg 1g - 100 g 1 cg=.018 18 = 1,000 mg 1 mg = .001 g Volume 1 kL = 1,000 L 1L = .001 Ki 1L = 100 CL 1 cl = .01L 1 L = 1,000 mL 1 mL = .001 L 1 mm = .001...
i dont understand why the molecular weight i calculated
(42.012 g/mol) for my unknown liquid (acetone) is less than the
actual molecular weight (58.08 g/mol). what errors could i have
made in my lab that would account for the difference.
Molecular Weight of a Volatile Liquid In this experiment, an amount of liquid more than sufficient to fill the flask when vaporized is placed in a flask of measured volume and mass. The flask is then heated in a boiling...
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