Question

87. main spring with k 1340 N/m is oriented vertically with one A end attached to the ground. A 7.27-kg bowling ball is dropped from 1.75 m above the top of the spring. Find the maximum Spring compression.
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Answer #1

let y is the maximum copmression.

Apply conservation of energy

loss of gravitational potential energy = gain in elastic potential energy in the spring.

m*g*(h + y) = (1/2)*k*y^2

7.27*9.8*(1.75 + y) = (1/2)*1340*y^2

on solving the above equation we get

y = 0.488 m <<<<<<<<<------------------Answer

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