how many grams of sodium hydrogen carbonate (MW 84.4) are needed to neutralize stomach acid (pH=2) if we assume all the H+ comes from HCL and the volume of the stomach is 950ml?
HCl + NaHCO3 ----> NaCl + CO2 + H2O
1 mol HCl = 1 mol NaHCO3
pH= 2 , [H3O+] = 10^-2 = 0.01 M
no of mol of H3o+ = HCl = 0.01*0.95 = 0.0095 mol
no of mol of NaHCO3 required = 0.0095 mol
amount of NaHCO3 required = 0.0095*84.4 = 0.802 g
how many grams of sodium hydrogen carbonate (MW 84.4) are needed to neutralize stomach acid (pH=2)...
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