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JU, I - 4, y = -1 = (4, -1) The solution is the ordered pair (4, -1) Check by substituting these values into the original equ

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Answer #1

Solution 1 x = y + 3 x+7=2y Put value of u from 1 to equation 2 (4+3)+7=24 3+7=2y-y y=10 -K2_4+3 lo+3 = 13. X=137-14=10 2 422

4 y=x+4 3uty = 16 Substitute value of y from_1 to ) 3 x + (1+4)= 16 44 + 4 = 16 4x = 12 X = 3 y = 3+4= 7 x=3 5) uty=2 3x+y=8

1) х+4= 5 2.x+y= 23 ч= 5- Substitute to eg. 2 2y + (5-1: { y=1 925-1-4 К.=1 y=4 3) х=-ч Зуу-lo Substitute 2 { от 1 40 41 . 2.

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