Question

3-5. Determine the force in each member of the truss. State if the members are in tension or compression. Assume all members are pin connected. Prob. 3-5 F OOO Noo 00 00 E 3 m 18 OO එ එ А B C D 2 m 2 m 2 m 5 kN 5 kN 5 kN

Answer 1

F AG 8m m.lt D A am am am Uskn SKN SKN @ jointo EV=0 5) FDEX 55 E FE FOE KN (T) D 3 C fo SH=07 FOEXUS = Fcp 5 KN es x 2 + fco (0) 7 FCO @ joint c {n=07 Fco - FBC f FCE FBC =) 80 kw (c) 3 c D B fco EV=0 FBC USKN FCE = 5 KN (T) @ joint E F FEF {:02) FEF X2 2.5 - For rent for 25 E FDE FEF - FBE + 25/ Ford B FCE 15 {v2o: FEEXIS 9.5 + FBEX 2.5 g) FCE + fofxls 25 FEF + FBE . 5x8.5 1.5 5x85 + 3 Fer Be : 16.67 KN CS Scanned with CamScanner

Sub in FBĘ + 25 + Foe o 16.67 FoE a 4.17 kn (c) FEF 12.5 KN (T) @ joint B f {veoa) Frf on FBEX!'5 2.5 ts FBF E FE + FBF 2) 7.5 KN (T) B A FAB C FBC SH:07 FREX² 25 & FAR & FBC 4.17 x 2 2.5 + FAB 80 3 FAB =) 3.33 kw (1) CS Scanned with CamScanner

@jont F G For F EV:09 FBF + fer x 3 = FAFX 3 5 FAF FEF NEBE E 7.5 +12.5x3 X3 FAF X3 A Vr3 B FAF 3) 18.027 KN (C) {H:07 FGF Far x2 + for VI3 verta 5 18.027x2 +12.5x4 V13 5 For = 20 kN (1) @joint a {V=0 5) VQ7 55+5+ 15 KN M sa HG F @joint G3 FG A VG = 15 KN (T) G Y FAG A CS Scanned with CamScanner