Question

Wild West produces two types of cowboy hats. A Type 1 requires twice as much labor time as a Type 2. If all the available lab
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Answer #1

T1 and T2 be the number of Type1 and Type2 hats produced respectively.

Let L = required labor hours for producing one unit of a Type2 hat.
So, 2L = required labor hours for producing one unit of a Type1 hat.

So, total labor hours required = 2L.T1 + L.T2

Again, we know that if all the available labor hours were dedicated to Type 2 alone, the company can produce a total of 400 Type 2 hats a day.

So, available hours = 400.L

So, the labor hour constraint will be 2L.T1 + L.T2 ≤ 400L or, 2T1 + T2 ≤ 400 (canceling out L from both the side)

Objective function: Maximize.Z = Toal Revenue = 8T1 + 5T2

Subject to,

2T1 + T2 ≤ 400 (labor hours)
T1 ≤ 150 (market limit of Type1)
T1 ≤ 200 (market limit of Type2)

T1, T2 ≥ 0

-----------------------------------

(a)

Type1 Type2
Qty. 100 200 Total
Revenue $8 $5 1800

B C D Set Objective: SE54 To: O Max Min value of: Total SUMPRODUCT($C$3:$D$3,04:04) ---------- Type1 Type2 Qty. 100 200 Reven

(b)

Final Reduced Objective Allowable Allowable
Cell Name Value Cost Coefficient Increase Decrease
$C$3 Qty. Type1 100 0 8 2 8
$D$3 Qty. Type2 200 0 5 1E+30 1
Final Dual Constraint Allowable Allowable
Cell Name Value Price R.H. Side Increase Decrease
$E$6 Labor hours Total 400 4 400 100 200
$E$7 Limit of T1 Total 100 0 150 1E+30 50
$E$8 Limit of T2 Total 200 1 200 200 100

(c)

The maximum allowable decrease for Type1 demand is 50 i.e. up to 100. The given decease is 120 i.e. within the range of feasibility. So, the dual price of 0 will be the same.

So, revenue will be 1800 - 0 x (150 - 120) = 1800 (same as before)

(d)

Dual price = 1

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