By equating the given curves, we have found out the values of and then the corresponding values of r are to be found out in the interval [0,2 ).
The step by step explanatory solution is provided below.
Problem 2. (a) Sketch the curves expressed here in polar coordinates r1=1+sin(0); r2 = 2 – sin(6). (b) Find the area of the plane region that lies inside both curves: r1=1+sin() and r2 = 2 - sin(0)
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1. Find another representation, (r, &theta), for the point under the given conditions. (154),r>0 and 2n<0<47 Select the best answer for the question 2. Find all the complex roots of 144(cos 210° + i sin 210°) in polar form. O A. 12(cos 210° + i sin 210°), 12(cos 195° + i sin 1959) O B. 12(cos 105° + i sin 105°), 195(cos 285° + i sin 285°) O C. 12(cos 105° + i sin 105°), 12(cos 285° + i sin...
Hi need help for these Questions: a. Given f = yi + xzk and g = xyz2, determine (∇ x f ) . ∇g at the point (1,0,3) b. Point A lies on the curve r(t) = 2 cos t i + 2 sin t j + t k for the range 0 ≤ t ≤ 2π . At point A, the tangent vector is T = - 21/2i + 21/2j + k. Determine the co-ordinates of point A and...
need help with these 4 questions Question 20 2 pts If a plane (2D) stress state in the x-plane gives a Moh's Circle and the two related points at corresponding toxplane) and corresponding to y plane as shown below. TA C(1,0) 26.6° MIO IN R = 2.24 Y Knowing the center for the Mohr's circles C11.00 MPa,OMPal and the radius R-224 MP how to find the direction in real geometry along which the normal stress reaches madu Within the plane...