Question

3. As an EPA scientist studying catalytic converters and urban smog, you want to find K. for the following reaction: 2 NO2 (g) = N2(g) + 2 02 (g) Kc = ? y N2 (g) + 12 02 (g) = NO(g) 2 NO, (g) = 2 NO(g) + O2 (9) K. = 4.8 x 10-10 Kc = 1.1 x 10-5

Answer 1

1/2 N₂ (g) + 1/2 O₂ (g) $\rightleftharpoons$ NO (g) ....(1)

So, K_c(1) = = 4.8 × 10^-10

NO [N2]1/2 [02]1/2

2NO₂(g) $\rightleftharpoons$    2 NO (g) + O₂ (g) ....(2)

so, K_c(2)$\rightleftharpoons$  
_{[NO][02] NO212}

2 NO₂ (g) $\rightleftharpoons$ N₂ (g) + 2O₂ (g).....(3)

Eq.3 = Eq.2 - (2 × Eq.1 )

= Keu NO₂72 [ No [Na]!/2 [027/2 = kc (1)

Kc = [Not [02] . [Na] [2] [Noz ] . [noj2 [N2] [02]2 [Noz Kc =

Equilibrium constant of reaction 3 is

K_c =
_{[N2] (0212 [NO2]}
= K_c(2) × [
_K1)
]

= 1.1× 10^-5 ×  ( )

(4.8 x 10-10)

= 0.048 × 10^-5 × 10²⁰

= 0.048 × 10¹⁵ .

= 4.8 × 10¹³ .