1. The four-byte sequence 0xA7 0xDB 0xDD 0x72 stored in consecutive memory cells in a little-endian...
1. The four-byte sequence 0xA7 0xDB 0xDD 0x72 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.
2. The four-byte sequence 0x8B 0x6A 0x73 0x86 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.
3. The four-byte sequence 0x22 0x88 0x8A 0x56 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit unsigned integer.
Homework Answers
1. The four-byte sequence 0xA7 0xDB 0xDD 0x72 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.
Answer:
The four-byte sequence 0xA7 0xDB 0xDD 0x72 stored in consecutive memory cells in a little-endian architecture represents 1927142311.0 (decimal) when interpreted as a 32-bit signed integer.
2. The four-byte sequence 0x8B 0x6A 0x73 0x86 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit signed integer.
Answer:
-2039256437.0 (with margin: 0 )
3. The four-byte sequence 0x22 0x88 0x8A 0x56 stored in consecutive memory cells in a little-endian architecture represents ___________ (decimal) when interpreted as a 32-bit unsigned integer.
Answer:
The four-byte sequence 0x22 0x86 0x82 0x56 stored in consecutive memory cells in a little-endian architecture represents1451394594.0(decimal) when interpreted as a 32-bit unsigned integer.
Add Answer to:
1. The four-byte sequence 0xA7 0xDB 0xDD 0x72 stored in
consecutive memory cells in a little-endian...
The unsigned decimal value (1,036)(base 10) is to be stored as a 16-bit word in memory....
The unsigned decimal value (1,036)(base 10) is to be stored as a 16-bit word in memory. a. Show the 16-bit unsigned binary representation of (1,036)(base 10). b. Show the 4-digit unsigned hexadecimal representation of (1,036)(base 10). c. The unsigned binary value of part (a) should be stored using two bytes of a byte-addressable memory at locations 400 and 401. Specify the hexadecimal value in each byte for a “big endian” instruction set architecture. Give your answer by showing a table.
Consider a 32-bit hexadecimal number stored in memory as follows: Address Value 100 2A 101 C2...
Consider a 32-bit hexadecimal number stored in memory as follows: Address Value 100 2A 101 C2 102 08 103 1B If the machine is big endian, what is the value stored at address 100-103 as an unsigned integer? If the machine is little endian, what is the value stored at address 100-103 as an unsigned integer?
1. A system with a word length of 32-bit and byte-addressable memory has ten consecutive 32-bit...
1. A system with a word length of 32-bit and byte-addressable memory has ten consecutive 32-bit signed numbers stored starting from memory location NUM. Write a RISC-style program to count the number of positive numbers in it and store the count in location COUNT.
A sixteen bit signed number, Y = 479 is to be stored in a byte wide...
A sixteen bit signed number, Y = 479 is to be stored in a byte wide memory system. The byte addressable storage for X in "BIG ENDIA N" format, $---- is: The byte addressable storage for Y in "LITTLE ENDIAN" format $---- is:
1) In a little endian memory system, assume the word 0xFFAABBCC is stored in memory address...
1) In a little endian memory system, assume the word 0xFFAABBCC is stored in memory address 0xFFFF0000. Then the byte at address 0xFFFF0002 is 0xAA TRUE FALSE Cyclic scheduling is more flexible and adaptive than round robin scheduling but 2) round robin is much easier to be implemented TRUE FALSE 3) The fundamental reason for building the memory hierarchy is due to the principle of locality, which includes the temporal locality and spatial locality. TRUE FALSE 4) Different threads spawned...
11. Suppose the 32-bit hex value ABCD4321 has been stored in memory starting at address 1000...
11. Suppose the 32-bit hex value ABCD4321 has been stored in memory starting at address 1000 (in decimal). Assuming byte-addressable memory, show the contents of the following memory locations if the machine is little endian and if it is big endian. address (in decimal) Contents in hex (Gif little endian) Contents in hex (if big endian) 1000 1001 1002 1003
Show how the following value would be stored by byte-addressable machines with 32-bit words by filling...
Show how the following value would be stored by byte-addressable machines with 32-bit words by filling in the appropriate memory locations, using big endian and then little endian format. Assume each value starts at address Ox10. VALUE: 0xF12 Address-Ox10 Big Endian Little Endian Ox11 0x12 0x13 0x14 Ox15
please show your steps and note that question 2 has a byte address of 000002 not...
please show your steps and note that question 2 has a
byte address of 000002 not 000000.
thanks
Hex Viewer Case Study to be used for questions 1: Review this excerpt from a hex viewer. You can assume that all data shown is in hex. You can assume that two's complement is used to store signed integers with a 16-bit architecture which is byte addressable. Refer to this excerpt to answer the questions below: 000000 8A00 8E00 CFA1 48BF 7900...
Write a program that allows the user to enter an unsigned integer (the maximum value of...
Write a program that allows the user to enter an unsigned integer (the maximum value of an unsigned 4-byte int is 232 = 4,294,967,296) and reverses its format (from little to big endian, or vice versa). Print out the user-entered number in hexadecimal and binary, reverse the endianness, and print the reverse in hexadecimal and binary. Integers in most machine architectures are represented in little endian format: the least significant byte is stored in the smallest address; for instance, the...
using the byte memory listed below write out the 32 bit word according to the listed...
using the byte memory listed below write out the 32 bit word according to the listed format Memory address 00 01. 02. 03 data. 11001100. 00001000. 11101011. 00110101 1.write the binary word in big Endian Format 2. Write the binary word in little Endian format
1. A system with a word length of 32-bit and byte-addressable memory has ten consecutive 32-bit signed numbers stored starting from memory location NUM. Write a RISC-style program to count the number of positive numbers in it and store the count in location COUNT.
A sixteen bit signed number, Y = 479 is to be stored in a byte wide memory system. The byte addressable storage for X in "BIG ENDIA N" format, $---- is: The byte addressable storage for Y in "LITTLE ENDIAN" format $---- is:
1) In a little endian memory system, assume the word 0xFFAABBCC is stored in memory address 0xFFFF0000. Then the byte at address 0xFFFF0002 is 0xAA TRUE FALSE Cyclic scheduling is more flexible and adaptive than round robin scheduling but 2) round robin is much easier to be implemented TRUE FALSE 3) The fundamental reason for building the memory hierarchy is due to the principle of locality, which includes the temporal locality and spatial locality. TRUE FALSE 4) Different threads spawned...
11. Suppose the 32-bit hex value ABCD4321 has been stored in memory starting at address 1000 (in decimal). Assuming byte-addressable memory, show the contents of the following memory locations if the machine is little endian and if it is big endian. address (in decimal) Contents in hex (Gif little endian) Contents in hex (if big endian) 1000 1001 1002 1003
Show how the following value would be stored by byte-addressable machines with 32-bit words by filling in the appropriate memory locations, using big endian and then little endian format. Assume each value starts at address Ox10. VALUE: 0xF12 Address-Ox10 Big Endian Little Endian Ox11 0x12 0x13 0x14 Ox15
please show your steps and note that question 2 has a
byte address of 000002 not 000000.
thanks
Hex Viewer Case Study to be used for questions 1: Review this excerpt from a hex viewer. You can assume that all data shown is in hex. You can assume that two's complement is used to store signed integers with a 16-bit architecture which is byte addressable. Refer to this excerpt to answer the questions below: 000000 8A00 8E00 CFA1 48BF 7900...
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