Question

In C++
2. Write a program that allows the user to enter a series of positive numbers between 1 and 100 and displays the smallest and largest of the numbers entered. The program should not store the numbers that were entered, only keep track of the smallest and largest ones. The program should continue accepting numbers until the value 0 is entered and then display the results. If a number out of range is entered, tell the user it is out of range and ignore it. This program should use a do while loop.

Answer 1

1 2 #include <iostream> using namespace std; 4- int main() { int smallest = 100, largest = 1, number; // declaring variables do{ cout << "Enter a number between 1 and 188: "; // taking user input cin >> number; if(number == 0) // breaking condition break; if(number <1 || number > 188) // out of range cout << "That is out of range." << endl; if(number <smallest) // updating smallest smallest = number; if(number > largest) // updating largest largest = number; }while(1); // looping cout << "Smallest = " << smallest << endl; // printing output| cout << "Largest = " « largest << endl; Execute Mode, Version, Inputs & Arguments Execute Execute - 0 Result CPU Time: 0.00 sec(s), Memory: 3268 kilobyte(s) compiled and executed Enter a number between 1 and 100: 1 Enter a number between 1 and 100: 25 Enter a number between 1 and 100: 75 Enter a number between 1 and 100: 109 Enter a number between 1 and 109: 0 Smallest = 1 Largest = 180

#include <iostream>
using namespace std;

int main() {
int smallest = 100, largest = 1, number; // declaring variables
  
do{
cout << "Enter a number between 1 and 100: "; // taking user input
cin >> number;
  
if(number == 0) // breaking condition
break;
  
if(number < 1 || number > 100) // out of range
cout << "That is out of range." << endl;
  
if(number < smallest) // updating smallest
smallest = number;
  
if(number > largest) // updating largest
largest = number;
  
}while(1); // looping
  
cout << "Smallest = " << smallest << endl; // printing output
cout << "Largest = " << largest << endl;
}

-- Please up vote or comment if you have any doubts. Happy Learning!