Question

I'm quite stuck with this C++ question, I would greatly appreciate the help!

Many companies use telephone number like 888- COM - CAST so the number is easier for their customer to remember. On a standard telephone, the alphabetic letters are mapped to numbers in the following fashion.

A, B, and C = 2

D, E, and F = 3

G, H, and I = 4

J , K , and L = 5

M, N, and O = 6

P, Q, R and S = 7

T, U, and V = 8

W, X, Y, and Z = 9

Write an application that asks the user to enter a 10 – character telephone number in the format xxx-xxx-xxxx. The application should

display the telephone number with any alphabetic characters that appeared in the original translated to their numeric equivalent. For

example, if the user enters 888-COM-CAST the application should display 555-266-2278.

Answer 1

#include <iostream>

#include <string.h>

#include <algorithm>

using namespace std;

int main(){

//delaring variable to store input of user

string Num;

cout<<"Please enter string to convert number";

cin>>Num;

for(int i=0;i<=Num.length();i++){

int j=1;

string r = Num.substr(i,j);

if(r=="A" || r=="B" || r=="C" ){

Num.replace(i,j, "2");

}else if(r=="D" || r=="E" || r=="F"){

Num.replace(i,j, "3");

}else if(r=="G" || r=="H" || r=="I"){

Num.replace(i,j, "4");

}else if(r=="J" || r=="K" || r=="L"){

Num.replace(i,j, "5");

}else if(r=="M" || r=="N" || r=="O"){

Num.replace(i,j, "6");

}else if(r=="P" || r=="Q" || r=="R" || r=="S"){

Num.replace(i,j, "7");

}else if(r=="T" || r=="U" || r=="V"){

Num.replace(i,j, "8");

}else if(r=="W" || r=="X" || r=="Y" || r=="Z"){

Num.replace(i, j, "9");

}

else{

}

j=j+1;

}

cout<<"Phone Number:"<<Num;

}