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Assume that the download times for a two-hour movie are uniformly distributed between 15 and 24 minutes. Find the following p

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Answer #1

Uniform distribution between a = 15 minutes and b = 24 minutes

a. P(less than 16 minutes) = P(X < 16)

= (16 - 15)/(24 - 15)

= 0.1111

b. P(more than 23 minutes) = P(X > 23)

= (24 - 23)/(24 - 15)

= 0.1111

c. P(between 17 and 22 minutes) = P(17 < X < 22)

= (22 - 17)/(24 - 15)

= 0.5556

d. Mean, \small \mu = (15+24)/2

= 19.5 minutes

e. Standard deviation, \small \sigma = \small (b-a)/\sqrt{12}

= \small (24-15)/\sqrt{12}

= 2.5981 minutes

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