Question

Insert Format Tools w Table Window Help < > + Reset all CSE 1: B Home MX https://ccse kennesa t 3 of 6 Automatic Zoom Assignment 2C: Can you still see the dots? It's an interesting time in display technology. When we talk about displays, you most often hear the term "pixel", which is the smallest light-emitting speck on your screen. We use the term "resolution" when talking about the total number of pixels on the screen, but sometimes you want to know how dense the pixels are per inch. A 4K giant display is common, but a 4K display on your iWatch would be a seriously impressive feat! The real question is, if someone came out with a 16K television, would you be able to see the individual pixels? If you couldn't, would you still buy it? So, in this assignment, we're going to calculate the pixels per square inch, very similar to an online calculator that does it. To calculate pixels per square inch, you need to know how many pixels there are horizontally (left-to-right), how many there are vertically (top-to-bottom), and the diagonal length of the display (upper-left to lower-right). According to the website, you have: Diagonal Pixels = Square root of (Vertical Pixels* + Horizontal Pixels) PPI = Diagonal Pixels / inches Examples of how to calculate the square root of a number is in the Appendix below. We need to use the sqrt function, which returns a double. Your job is to write a program that reads in the horizontal and vertical resolution of the screen as well as its diagonal length (in inches) and print out the number of pixels per square inch. Note: you cannot have part of a pixel (e.g. 216.9), so you must round down to the nearest whole pixel. The easiest way to do this is type-cast from a float (or double) to an int. Sample Output: Horizontal pixels: 2880 Vertical pixels:

Answer 1

HERE IS THE REQUIRED SOLUTION IN C++

HERE IS THE C

1 #include <iostream> 2 #include<math.h> 3 using namespace std; 4 int main() 5-{ int horizontal_pixel, vertical_pixel, diagonal_inches, diagonal_pixels; 6 float PPI; 7 cout<<"Horizontal pixel:\n"; 8 cin>>horizontal_pixel; 9 cout<<"vertical pixel: \n"; 10 cin>>vertical_pixel; 11 cout<<"Diagonal in inches: \n"; 12 cin>>diagonal_inches; 13 diagonal_pixels(int)sqrt(horizontal_pixel*horizontal_pixel+vertical_pixel vertical_pixel); 14 PPI=1.** diagonal_pixels/diagonal_inches; 15 cout<<"Pixel per square inchis :"<<PPI PPI; 16 17 return; 18 ] 19 input Horizontal pixel: 1920 vertical pixel: 1080 Diagonal in inches: 10 Pixel per square inchis : 48488 Us - - Program finished with exit code 0 D. ENTER to exit console. Diler#tah-stdin

#include <iostream>
#include<math.h>
using namespace std;
int main()
{ int horizontal_pixel,vertical_pixel,diagonal_inches,diagonal_pixels;
float PPI;
cout<<"Horizontal pixel:\n";
cin>>horizontal_pixel;
cout<<"vertical pixel:\n";
cin>>vertical_pixel;
cout<<"Diagonal in inches:\n";
cin>>diagonal_inches;
diagonal_pixels=(int)sqrt(horizontal_pixel*horizontal_pixel+vertical_pixel*vertical_pixel);
PPI=1.0*diagonal_pixels/diagonal_inches;
cout<<"Pixel per square inchis :"<<PPI*PPI;

return 0;
}

ODE