Question

0.6 F100jN 0.2 10.6 8. The magnitudes of the forces are Fi- 20.0 kN, F2-80.0 kN, F3 57.0 kN, and F4 36.0 kN. Calculate the resultant of the force system, and express it as a force and a couple moment with respect to the point Calculate the angle between FR and MRA. Explain why this system cannot be simplified in the same way as Problem 6. 1.0 1.0 0.1 All dimensions in meters 0.6 0.3

Answer 1

CG^^= CG^-/ Vertical-bar CG^- Vertical-bar = -1.1 i + j + 8.2 k/1.5 DF vector = DF^-/ Vertical-bar DF^- Vertical-bar = -1.7 i + 0.6j - 0.6/1.9 Therefore In all i n lessthanorequalto N The values F_1^- = -20 j F_2^- = -80 j F_3^- = F_3 times DF^- = 57 (-17i + 0.6j - 0.6k)/1.9 Therefore F_3^- = -51i + 34.2 j - 34.2 k F_4^- = F_4 times CG^- = 36 (-1.1i + j + 6.2 k)/1.5 F_4^- = -26.4 i + 24j + 4.8 k \r\n Therefore sigma F = h, F_1^- + F_2^- + F_3^- + F_4^- = R^- R^- = (-20 j) + (-80 j) + (-51i + 34.2 j - 34.2 k) + (-26.4 i + 24j + 4.8 k) R^- = (-77.4i - 41.8 j - 29.4k) kN sigma M_about A (F) = sigma M_about A (R) = AB^- times F_1^- + AE^- times F_2^- + AD^- times F_3^- + AC^- times F_4^-