Question

3. A rich fuel-air ratio of propane in burned in an internal combustion engine. The analysis exhaust gas by the exhaust analyzer shows that CO2 = 17%, C3H8=0.5%, with the rest being N2 and some traces of H20. For this case Calculate: a) Write the balanced chemical equation for propane b) Compute air-fuel ratio and equivalence ratio when the ideal AFR is 14.8 ran

Answer 1

Thank uou. I have answered all the parts for combustion of propane. Please like the answer ASAP.

for Burning of Propane GH) we haves @ Balanced chemical equation is 1.C3 Hg + 50, 3 CO₂ + 4H20) 0.5% Cllg is unburnt O Fox Aid fuel Ratio nals of air SX 32 (Stoichiometric) 36+8 mass of fuel TAFR = 3.64 AFRO/.0.21 23.8 2+2) Actual AAR Equivalence Ratio = Stoichmetic AFR .. Equivalent Ratio = Ideal AFR Stoicheometric AFR 14.8 = 0.6216 0,2 - 9+ b с 23.8 - Equivalence Ratio=0.62167, which shows Hlean cumbustion. onygen (air). with excel