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< Question 10 of 18 > “To calculate AG for an ion, you simply add the equations for the chemical and electrostatic components

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∆G = 2.303 RTLog (ca2+ in/ ca2+ out)+ nExF

∆G= 2.303 x8.314x310xlog(0.1/2.1)+2x-60x10^-3x96500

∆G=5935.61x-1.3- 11580= -7716.35-11580= -19296= -19.3kj/mol

Hope it's clear..thanks

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