∆G = 2.303 RTLog (ca2+ in/ ca2+ out)+ nExF
∆G= 2.303 x8.314x310xlog(0.1/2.1)+2x-60x10^-3x96500
∆G=5935.61x-1.3- 11580= -7716.35-11580= -19296= -19.3kj/mol
Hope it's clear..thanks
< Question 10 of 18 > “To calculate AG for an ion, you simply add the...
Resources Hint "To calculate AG for an ion, you simply add the equations for the chemical and electrostatic components together. (02) Say you are trying to move Cat into a frog muscle cell through its ionotropic Ach receptors after they are stimulated by the neurotransmitter. For a typical frog muscle cell, the concentration of Ca2+ is 0.100 mM inside the cell and 2.10 mM outside the cell. As mentioned earlier, a typical animal cell resting membrane potential is -60 mV,...
Given these parameters, what is the AG for K ion transport into the frog muscle cell in the presence of Ach? Dr. Knowsalot smiles and nods. "Good," she says. "Now let's see whether K+ ions pass through the open Ach receptors into the cell. As you might remember, these channels are permeable to Na+, K+, and Ca2+. For a typical frog muscle cell, the concentration of K+ is roughly 124 mM inside the cell and 2.30 mM outside the cell."...