Question

y es ASK TOP cher A mechanic applies a torque to a nut with a wrench 0.300 m long. Because of the cramped space, he must evert a force upward at an angle of 58.0 with respect to a line from the nut through the end of the wrench If the force he exerts has magnitude 82.0 N what magnitude torque inm ) does he apply to the nut (Assume that the force is applied at the end of the wrench) HINT

Answer 1

Length of wrench =r=0.300m Angle of force with line from nut through end of the wrench = 0=5800° Magnitude of force exerted = f = 82.0N the Wrench - out Nut e 2 Now, Torque of a force (f) about a point which is at a distance r from line of force and making an angle o with force is giren by z = fr sino =) z = 182.0N) 10.300m) sin 158.00) > z=2406 40.848 Nm =) Z=20-8608 Nmã 2009 Nm So, magnitude of torque about nut is 2009 Nm