Question

A jet airliner moving initially at 2.85 102 mi/h due east enters a region where the wind is blowing at 1.00 102 mi/h in a direction 33.5° north of east. (Let the x-direction be eastward and the y-direction be northward.)

A jet airliner moving initially at 2.85 x 102 mi/h due east enters a region where the wind is blowing at 1.00 x 102 mi/h in a direction 33.5° north of east. (Let the x-direction be eastward and the direction be northward (a) Find the components of the velocity of the jet airliner relative to the air, v1a 285 (b) Find the components of the velocity of the air relative to Earth, VAE. mi/h VAL 83.38 mi/h 55.19 VAF,y (c) write an equation analogous to VAB VAE Vee for the velocities vyAr VAE, and VUE, (Use the following as necessary: VAE and VE In the given equation, VeE is the velocity of observer B relative to observer E. object A travels with velocity vAR relative to observer B, and velocity VAF relative to observer E (368.38) (55.19)) (d) What are the speed and direction of the aircraft relative to the ground? magnitude 372.49 mi/h north of east direction 8.52 Need Help? Talk to a Tutor

Answer 1

Break the wind down into components (north and east) and add the wind speed to the airliner's speed.

285 + 100cos(33.5°) = 368.39 mph E
0 + 100sin(33.5°) = 55.19 mph N

Then use the pythagorean theorem to find the magnitude, and tangent to find the direction.

√[368.39² + 55.19²] = 372.501 mph
tanθ = 55.19 / 368.39 = ~ 0.1498

Calculations maybe wrong, logic is correct.

Hope this helps !! :)