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Question 7 Not yet answered Marked out of 2.00 Flag question The cross section dimensions of a metal rod is (0.007 m x 0.007 m), its length is 1000 mm. The allowable stress is 200 MPa. An axial force (longitudinal force) is applied to this rod. 1. The force changes the section dimension to be (0.006 mx 0.006 m), so the type of this force is 2. Due to this change in section dimensions, the new length will be

Answer 1

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Given dimeusions of metal 910d befile application of 0108s Section = 0.007mX 0.004M - bxd = HEDO M Imm x 7 mm. 'Tengiti of roolt= 1000 mm After application of stress. Stress = 900 MDA = 200XLOW NIM? = 200N/mm2 The changed cross section = 0.000m x0006m = 6MM X 6mm. 1. As the 1055 Section of the god is deceas ie the rod is extended So, the applied axial load is tensile 2. For new length Strain in lateral direction, e= $b - 6776 4-6 200 We Know, young's moduls, E= Strain € = 1400 N/mm2. Se a member - 200X108P_5 1420 6.5mm 5. Original length ' = 1+80 = 1000 +142.69 - 1142.85mm

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