Question

EDIT: The fluid in the system is water. There is no data regarding the inclination of the pipe. It's known that the equipment used includes a fluid flow piping system (AFT), hydraulic bench (FME00), barometer, and psychrometer. Also added an appendix that has recommended equations.

Appendix B: Water properties Basic Equations 1. Flow Rate: Q=V* A (m/s) A = Cross sectional area, ma V = Velocity, m/s; 2. Reynolds Number: | M = *D D = Diameter, m; n= Kinematic viscosity, m-/s. If NR <2000 → Laminar flow; if NR > 4000 → Turbulent flow 3. Darcy's equation for turbulent flow L . hp = 3 6 28 (m) Where: h = Head loss, m; f= Friction factor L = Length, m; D = Diameter, m; g = gravitational constant, m/s2 Table 1B. Data reduction template Reading Flow Velocity Viscosity | A Head | Friction # rate m/s m/s (m /s) factor, f Ne Ln(NR)

Need help on a fluid mechanics friction problem

Given:

Pipe Diameter=23mm

Length=1000mm

Temperature = 70 Celsius

Flow rate = 1400 L/hr

Water column LP1= 330mm

Water column LP2=90mm

Find:

Flow rate m^3/s, Velocity m/s, Temp C, Viscosity (m2/s) Reynolds No. Head loss, hl m, Friction f

Answer 1

L=10oomm = rmo D = 23 mm = 0.023m 02 sh=LPI-LP2 = 330 -90 = 240 -0.24m flow rate a= 1400l/hr. = 3.88 x10km/h Temperature=100 density fo = 980.39 kg/m3 Applyming Bernaullis equation @ @ Pi + 2 + 1 = 2 + V2 + Z2th – 6 fg ag f8 2g to 1. Flow Rate see Q=14004 /ho= 3.88x10 4 in = V& A = 3.88810 (TIX0.023) & Velocity = - 0.934 m/sec. No. Re = VxD = Nr. 2. Reynolds V- kremetic viscosity at 78c, water - MB= 0.400 XTOS - 4.084107 980.39 No- Re=0.934 x 0.023 =52651.96 4.088107