alue 55 points 10 attempts left Check my work Be sure to answer all parts. Calculate...

Question

Question

Answer 1

Answer #1

molarity of KOH = 0.26M

volume of solution = 7.7ml = 0.007L

no of moles of KOH = molarity * volume in L

= 0.26*0.007 = 0.00182moles

KOH(aq) --------------> K^+ (aq) + OH^- (aq)

0.26M 0.26M

[OH^-] = [KOH]

[OH^-] = 0.26M

POH = -log0.26 = 0.585

Answer 2

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