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A motor spins up from rest to an angular velocity of 265 rad/s in 3 s....

A motor spins up from rest to an angular velocity of 265 rad/s in 3 s. Treat the motor as a cylinder of mass 3 kg and radius 0.3 meters. Find the rotational work done by the motor after it rotates though 12 revolutions.

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Answer #1

Here it is mentioned that motor as a cylinder so I am treating it as a solid cylinder ( like a big disc) Hence i am using a formula for moment of inertia of a solid cylinder of mass m and radius r is given by I = (1/2) mass x radius 2

since motr spins uttro mest there ore iníHol usherと 仄 angular qcceler-qt\.0 .is ushere. I = moment 여 inextra of cylinder workAl ternal method u)二.ugo t.ィ七 2 2 KE = 898.668 Jade Rotatimal Wart dme b the motox is eo 。als to the Rotdin ke.and hence Wこ81

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