Question

7. A few weeks ago, a material was discovered on the campus of LATTC deep in 4th floor of the C4 building. The material, Navarroium (Na), has a measured density of 2.71 g/cm' and atomic weight of 26.98 g/mol. To have a complete understanding of Na, determine how many atoms are found in a mº of the material.

Answer 1

Given :- density = 2.71 g/cm3 atomic weight = 26.98 g/mol B Caw) het w = weight of atom AW = atomic weight of atom N = number of atoms NA Avagadro's number = 6.022 x1623 n = number of moles Then → Les KAW) — 0 We know that density = . mass volume mass (w). NA TAW volume = 1 m3= 106 cm² density = 2.71 g/cm3

density - everyo ne 2.71 = x Aw 106 x 26.98 2.71 - - 6.0227133 105 23 N = 2-71 X 10 x 6.022 x 10 26.98 NE 6.048x1048) atoms in Imo g material .
there are 6.048×10^28 atoms in 1 m3 of material