Question

an unsaturated solution 6. Briefly explain the reason why a drastic increase in water temperature in a small body of water would have an impact on aquatic wildlife. 7. If 0.457 g of anhydrous sodium carbonate reacted with exactly 22.55 mL of dilute hydrochloric acid solution, calculate the concentration of hydrochloric acid. Na,Co, + 2HCl -> 2NaCl + H,O + CO,

Answer 1

6. As we know aquatic wildlife need oxygen in order to survive, for energy requirements.

At the same time solubility of oxygen in water decreases with rise in the temperature, therefore due to drastic increase in the temperature, there will be deficiency of the oxygen, and there will be problem of surviving,

Question 7.

Moles of sodium carbonate = mass/molar mass = 0.457/106 = 0.00431 moles

Using mole mole analysis, moles of HCl needed for the reaction = 2× 0.00431 = 0.00862

Volume = 22.55 ml = 22.55/1000 = 0.02255 L

So concentration = moles/volume = 0.00862/0.02255 = 0.382 M

Concentration = 0.382 M (mol/L)

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