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Question 2 O out of 35 points A diver jumps off a cliff of heighth at angle - 49 (we figure). He reaches a maximum height of
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Voy VeSin49* hmax =y= 1sm 49 Vox = Vo Cos49 g= 40m1s2 heigut Sin49= o.547 of clitf X= 236 m H+(Vo Sin4gt) - 2XIot2 5t2-Vo SiBy ei.01 (15.674)2 x 5- 22.95 X O07547 - H=0 17.32 1228. 371 H 1211-05 meter Heignt of the cliff 1211.051 m CH) =

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