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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standar

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The solution is done showing all steps with calculations and required explanations. For your better understanding, a z table is also attached. Hope you can understand and appreciate the work.

X Let Z = X-M Let x denotes the defect length of a corrosion effect. N(Mean = M =28, standard. Deviation - 7.2) x-M NCO,) le

be (c mm (d) Smallest 10% PCX <s) - 0.10 O, PCXML625 ) - 0.10 G = 0.10 = (1.28) c-28 oly 7.2 -) e-28 7:2 -- 128 9, c - 28-1:

z table :

Z 0.0 0.1 02 03 0.4 05 0.6 0.7 0.8 0.9 1.0 1.1 12 13 14 15 1.6 17 18 1.9 2.0 21 22 23 2.4 25 2.6 2.7 2.8 2.9 3.0 3.1 3.2 3.3

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