As a calculated percentage, how efficient is a synchronous data link protocol whose frames include 24 overhead bytes (frame delimiters, head fields, error check field, etc.) and a 1524-byte data field?
Efficiency can be calculated by the no.of information bits transmitted by the total no.of bits in the transmission.
Here no.of information bits = 1524*8 (1 byte= 8 bits) = 12192
bits
Total bits transmitted = information+ overhead bits = (1524+24)*8 =
12384
Efficiency = 12192/12384= 0.9844
% Efficiency = Efficiency X 100 = 98.44%
As a calculated percentage, how efficient is a synchronous data link protocol whose frames include 24...
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