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Number of Unknown Sample Mass of Beaker #1 and Sample a-b=2,129 52.4779 - 50.348g 2.1299 -B0.35g...
Hey, i need help with the data analysis part of my HW. Thank You! Mass of...
Hey, i need help with the data analysis part of my HW. Thank
You!
Mass of beaker (e) Trial I Trial 2 2 Mass of beaker and salt mixture (g) Mass of salt mixture (g) O63.9 1.2325 4 Mass of filter paper (e) 1,239 Mass of filter paper and product after air-dried oroven-dried (g) 1.S149 6Mass of dried product (g) 0.2824 252 CalaD,0 1. Formula of dried product CaCaOnHyO 0.2929 B. Determination of Limiting Reactant L. Limiting reactant in salt...
is this right? Step No. 1. Identity Number of the Unknown 3. Mass of test tube...
is this right?
Step No. 1. Identity Number of the Unknown 3. Mass of test tube and total unknown 83.138 5. Mass of test tube and about half unknown g 1-978 7. Mass of test tube (empty) laeall # 2 #1 Mass of filter paper 12. Mass of filter paper and Cu Mass-of filter paper and-Cu 18. 20a. g Calculate Beaker #2 Beaker #1 Lఏ 1 Mass of Unknown sample 21 20b. Mass of recovered copper 22. e by mass...
Data Mass of Beaker 1 Mass of Beaker 1 +CaCl2 Mass of Beaker 2 Mass of...
Data Mass of Beaker 1 Mass of Beaker 1 +CaCl2 Mass of Beaker 2 Mass of Beaker 2 + KIO Mass of Watch Glass + Filter Paper 113.3949 114.4089 130.7249 13 2.0769 58.340g 59. Sisg _59.3213 131.6489 131.6349 Mass of Watch Glass + Filter Paper + Ca(IO3)2(after 1" Heating) Mass of Watch Glass + Filter Paper + Ca(IOsh(after 2nd Heating) Mass of Beaker 2 + Residue (after 1" Heating) Mass of Beaker 2 + Residue (after 2nd Heating) Calculations (Show...
Questions 1-4 Before reaction: a. unknown number b. weight of beaker, test tube weight of beaker,...
Questions 1-4
Before reaction: a. unknown number b. weight of beaker, test tube weight of beaker, test tube, KCIO3 KCI d. weight of beaker, test tube, KCIO3 KCI. Mno2 e. weight of KCIO3 KCl sample (c-b) After reaction: f. volume of oxygen collected at laboratory temperature and pressure -22.3% 246.3 n (determined by the amount of water expelled from the flask g. temperature of the oxygen h. water vapor pressure at the measured temperature (table: Handbook of Chemistry and Physics)...
i need help with data Analysis Experiment & Report Sheet Limiting Reactant Desk No. to Lab...
i need help with data Analysis
Experiment & Report Sheet Limiting Reactant Desk No. to Lab Sec. - Lab Sec. Name Precipitation of CaC,OH,O from the Salt Mixture Unknown number_ 2 I Mass of beaker() Mass of beaker and salt mixture (8) Trial Trial 2 3. Mass of salt mixture (8) 4. Mass of filter paper() 5. Mass of filter paper and product after air-dried roven-dried (e) 6. Mass of dried product() (NEE with 0.3889 0.6189 -0.280T0 Cal2o4•H2O 0.998 g...
Mass of 150ml, beaker: Mass of beaker, filter paper, and 30.10 copper (11) phosphate after drying:...
Mass of 150ml, beaker: Mass of beaker, filter paper, and 30.10 copper (11) phosphate after drying: Mass of copper (ll) phosphate produced: (actual yield) Percent yield of copper (11) phosphate: B. DETERMINATION OF THE COMPOSITION OF A MIXTURE OF SO- DIUM PHOSPHATE AND SODIUM CHLORIDE 3.28 of o Mass of mixture: Balanced chemical equation: 2NA PO + 3aul -> Cua (P)+6 Nace 61.52 32 220.65% Mass of CuCl, necessary: (show calculation) 329. Nas fou wel Nesply 13 mol Cucts 120.489...
Question 2,3,4 please. ESTIONS: 1. Many students do not recover 100% of the original mixture. Describe...
Question 2,3,4 please.
ESTIONS: 1. Many students do not recover 100% of the original mixture. Describe at least two possible problems that could cause less than 100% recovery of the mixture. 2. A student received a mixture that actually contained 50.0% salt and 50.0% sand. At the end of the experiment, this student calculated that his sample was composed of 45.2% salt and 54.8% sand. What might he have done (or not done correctly) during the experiment to cause this...
Name: Lab Partner(s): Data Sheet volume of unknown sample (mL) Bad UD-om mass of filter paper (g) mass of filter p...
Name: Lab Partner(s): Data Sheet volume of unknown sample (mL) Bad UD-om mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) 0.339 1.479 Calculation: mass of solid Ba3(PO4)2 (9) filter paper -- Total 1647g-0-339 = 1.149 11.149 molar mass of Baz(PO4)2 (a/mol) molar mass of BaCl2 (g/mol) Calculation mass of Bach orignally present in the unknown sample (9) Calculation: g of BaCl2 per mL of sample (g/mL) Calculation: Actual calculated value of BaCl2 (g/mL) 0.0125 Experimental Error...
5. An unknown metal carbonate was analyzed gravimetrically and yielded the following data. Calculate the values...
5. An unknown metal carbonate was analyzed gravimetrically and yielded the following data. Calculate the values for lines d - i. a. Mass of dried M2CO3 1.972g b. Mass of filter paper 0.598g c. Mass of filter paper +CaCO3 2.436g d. Mass of CaCO3 (c-b) e. Moles of CaCO3 f. Moles of M_C03 (= e) g. Molar mass of M_C03 (a/f) h. Identity of M.CO i. Percent error Show your calculations here:
Limiting reactant help?? Unknown number Pial Tared mass of salt mixture (g) 1003 2 209-30Bg Mass...
Limiting reactant help??
Unknown number Pial Tared mass of salt mixture (g) 1003 2 209-30Bg Mass of filter paper (g) . Mass of filter paper and Ba(PO,) (g) 4. Mass of Ba,(PO)(g) . Determination of Limiting Reactant . Limiting reactant in salt mixture (write complete formula) 2. Excess reactant in salt mixture (write complete formula) ata Analysis 1. Moles of Ba,(PO, precipitated (mol) 2. Moles of limiting reactant in salt mixture (mol) Naa P04 Jodium phosphate barinnn ch10万de . formula...
Hey, i need help with the data analysis part of my HW. Thank
You!
Mass of beaker (e) Trial I Trial 2 2 Mass of beaker and salt mixture (g) Mass of salt mixture (g) O63.9 1.2325 4 Mass of filter paper (e) 1,239 Mass of filter paper and product after air-dried oroven-dried (g) 1.S149 6Mass of dried product (g) 0.2824 252 CalaD,0 1. Formula of dried product CaCaOnHyO 0.2929 B. Determination of Limiting Reactant L. Limiting reactant in salt...
is this right?
Step No. 1. Identity Number of the Unknown 3. Mass of test tube and total unknown 83.138 5. Mass of test tube and about half unknown g 1-978 7. Mass of test tube (empty) laeall # 2 #1 Mass of filter paper 12. Mass of filter paper and Cu Mass-of filter paper and-Cu 18. 20a. g Calculate Beaker #2 Beaker #1 Lఏ 1 Mass of Unknown sample 21 20b. Mass of recovered copper 22. e by mass...
Data Mass of Beaker 1 Mass of Beaker 1 +CaCl2 Mass of Beaker 2 Mass of Beaker 2 + KIO Mass of Watch Glass + Filter Paper 113.3949 114.4089 130.7249 13 2.0769 58.340g 59. Sisg _59.3213 131.6489 131.6349 Mass of Watch Glass + Filter Paper + Ca(IO3)2(after 1" Heating) Mass of Watch Glass + Filter Paper + Ca(IOsh(after 2nd Heating) Mass of Beaker 2 + Residue (after 1" Heating) Mass of Beaker 2 + Residue (after 2nd Heating) Calculations (Show...
Questions 1-4
Before reaction: a. unknown number b. weight of beaker, test tube weight of beaker, test tube, KCIO3 KCI d. weight of beaker, test tube, KCIO3 KCI. Mno2 e. weight of KCIO3 KCl sample (c-b) After reaction: f. volume of oxygen collected at laboratory temperature and pressure -22.3% 246.3 n (determined by the amount of water expelled from the flask g. temperature of the oxygen h. water vapor pressure at the measured temperature (table: Handbook of Chemistry and Physics)...
i need help with data Analysis
Experiment & Report Sheet Limiting Reactant Desk No. to Lab Sec. - Lab Sec. Name Precipitation of CaC,OH,O from the Salt Mixture Unknown number_ 2 I Mass of beaker() Mass of beaker and salt mixture (8) Trial Trial 2 3. Mass of salt mixture (8) 4. Mass of filter paper() 5. Mass of filter paper and product after air-dried roven-dried (e) 6. Mass of dried product() (NEE with 0.3889 0.6189 -0.280T0 Cal2o4•H2O 0.998 g...
Mass of 150ml, beaker: Mass of beaker, filter paper, and 30.10 copper (11) phosphate after drying: Mass of copper (ll) phosphate produced: (actual yield) Percent yield of copper (11) phosphate: B. DETERMINATION OF THE COMPOSITION OF A MIXTURE OF SO- DIUM PHOSPHATE AND SODIUM CHLORIDE 3.28 of o Mass of mixture: Balanced chemical equation: 2NA PO + 3aul -> Cua (P)+6 Nace 61.52 32 220.65% Mass of CuCl, necessary: (show calculation) 329. Nas fou wel Nesply 13 mol Cucts 120.489...
Question 2,3,4 please.
ESTIONS: 1. Many students do not recover 100% of the original mixture. Describe at least two possible problems that could cause less than 100% recovery of the mixture. 2. A student received a mixture that actually contained 50.0% salt and 50.0% sand. At the end of the experiment, this student calculated that his sample was composed of 45.2% salt and 54.8% sand. What might he have done (or not done correctly) during the experiment to cause this...
Name: Lab Partner(s): Data Sheet volume of unknown sample (mL) Bad UD-om mass of filter paper (g) mass of filter paper + solid Ba3(PO4)2(g) 0.339 1.479 Calculation: mass of solid Ba3(PO4)2 (9) filter paper -- Total 1647g-0-339 = 1.149 11.149 molar mass of Baz(PO4)2 (a/mol) molar mass of BaCl2 (g/mol) Calculation mass of Bach orignally present in the unknown sample (9) Calculation: g of BaCl2 per mL of sample (g/mL) Calculation: Actual calculated value of BaCl2 (g/mL) 0.0125 Experimental Error...
5. An unknown metal carbonate was analyzed gravimetrically and yielded the following data. Calculate the values for lines d - i. a. Mass of dried M2CO3 1.972g b. Mass of filter paper 0.598g c. Mass of filter paper +CaCO3 2.436g d. Mass of CaCO3 (c-b) e. Moles of CaCO3 f. Moles of M_C03 (= e) g. Molar mass of M_C03 (a/f) h. Identity of M.CO i. Percent error Show your calculations here:
Limiting reactant help??
Unknown number Pial Tared mass of salt mixture (g) 1003 2 209-30Bg Mass of filter paper (g) . Mass of filter paper and Ba(PO,) (g) 4. Mass of Ba,(PO)(g) . Determination of Limiting Reactant . Limiting reactant in salt mixture (write complete formula) 2. Excess reactant in salt mixture (write complete formula) ata Analysis 1. Moles of Ba,(PO, precipitated (mol) 2. Moles of limiting reactant in salt mixture (mol) Naa P04 Jodium phosphate barinnn ch10万de . formula...
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