Z=ABC+AB'C+AB'C'+A'B'C
=AC+AB'C'+A'B'C
=A(C+B'C')+A'B'C
=A(C+B')+A'B'C
=AC+AB'+A'B'C
=AC+B'(A+A'C)=AC+B'(A+C)=AC+B'A+B'C
Option A: Simplifies to (A+B')C=Ac+B'C
Option C: Simplifies to AB'C'+B'C+AC=AC+B'(C+AC')=AC+B'C+B'A
Option D: Simplifies to AC+B'C+AB'
Hence option C is correct
computing in Math Consider the following truth table with input variables A, B and C: A...
Given the following truth table, where X, Y, and Z are input and W is output, write the canonical expression and generate gate-level logical circuit (draw the wire diagram). Given the following truth table, where X, Y, and Z are input and W is output, write the canonical expression and generate gate-level logical circuit (draw the wire diagram). 0 01 0 0 100O 0 110 (0
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