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The peak current passing through an inductor is 2.0A. What is the peak current if a....

The peak current passing through an inductor is 2.0A. What is the peak current if

a. The peak emf is doubled

b. The inductance L is doubled

c. The frequency is doubled

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Answer #1

Here ,

peak current , Ip = 2 A

as the peak current is

Ip = peak voltage/

Ip = peak voltage/(j * 2*pi * f * L)

hence , for doubling the current

a. The peak emf is doubled

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