I need help with question 2, 3 and 4 please. Thanks in advance.
2) Given,
f(n) = 4 nlogn + 4 n^2 + 4 n
To find the 'O' notation, we need to find the degreee of the the
above polynomic equation. The degree of a polynomial will be the
highest degree of individual. The degree of above polynomial is
'2'.
so, it will be O(n^2). //Hence proved.
3) There will be many such f1 and f2 functions. Let g(n) be n^2.
As, f1 is not O(f2(n)),
We can have f1(n) = n^2+log n+1 and f2(n) = n^2
4) Given, f(n) is 0(g(n)).
We know for any polynomial P, 2^P is 0(2^0(p))
so, 2^f(n) is 0(2^g(n))
4.b) f(n) + g(n) for sum of polynomial big 0(f,g) wil be minimum. so, this is valid.
4.c) for a polynomial we do not consider constant while
calculating 0(). so
for 2^na big O is O(2^n)
I need help with question 2, 3 and 4 please. Thanks in advance. Answer the following...
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