A 65 kg snowboarder travels down a 37° incline at 6.2 m/s. In order to stop...
A 65 kg snowboarder travels down a 37° incline at 6.2 m/s. In order to stop before hitting a tree, the snowboarder quickly turns their board to increase the coefficient of kinetic friction to 1.9.
What is the normal force between the snowboarder and the ground?
What is the friction force between the snowboarder and the ground?
How far does the snowboarder slide before stopping? Assume the path the snowboarder takes is straight down the slope.
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A 65 kg snowboarder travels down a 37° incline at 6.2 m/s. In
order to stop...
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A car (m = 2000 kg) is traveling down a 15 degree incline at 65 m/s. The driver slams on the breaks causing the wheels to lock. Omega_x = 0.3. How far S will the tires skid on the road? If the driver can skid only 10 m before hitting another vehicle, how fast will the driver hit the other vehicle?
A 20 kg crate is allowed to slide down a 60-m long smooth inclined plane which...
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a A 2.0 kg breadbox on a incline of angle 8 = 30° is connected, by a cord that runs over a pulley, to a light spring of spring constant k = 120 N/m, as shown in the Figure 4. The coefficient of kinetic friction between box and the inclined plane is Mik = 0.52, The box is released from rest when the spring is unstretched. Assume that the pulley is massless and frictionless and the system is isolated. (a)...
Problem #3 In the diagram below, m; = 0.60 kg is sliding down the incline with...
Problem #3 In the diagram below, m; = 0.60 kg is sliding down the incline with an initial speed of 2.5 m/s and ma is initially motionless. mslides through distance d = 1.50 m before colliding elastically with m2 -0.80 kg. m2 later comes to rest my moves frictionlessly, and the coefficient of kinetic friction between me and the incline is 0.70. (a) A diagram illustrating the initial “situation of interest" is given below. Draw diagrams illustrating all other relevant...
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A 3.70-kg block starts from rest at the top of a 30.09 incline and slides a distance of 1.90 m down the incline in 1.20 s.
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A car (m = 2000 kg) is traveling down a 15 degree incline at 65 m/s. The driver slams on the breaks causing the wheels to lock. Omega_x = 0.3. How far S will the tires skid on the road? If the driver can skid only 10 m before hitting another vehicle, how fast will the driver hit the other vehicle?
A 20 kg crate is allowed to slide down a 60-m long smooth inclined plane which is 30° with the horizontal. At the bottom of the inclined plane, the crate is allowed to slide horizontally with the ground where the coefficient of friction between the crate and the ground is 0.15. After 1 m, the crate would meet a coil with a spring constant of 1000 N/m. (Assume that the friction no longer acts as the crate hits the spring).Calculate...
a A 2.0 kg breadbox on a incline of angle 8 = 30° is connected, by a cord that runs over a pulley, to a light spring of spring constant k = 120 N/m, as shown in the Figure 4. The coefficient of kinetic friction between box and the inclined plane is Mik = 0.52, The box is released from rest when the spring is unstretched. Assume that the pulley is massless and frictionless and the system is isolated. (a)...
Problem #3 In the diagram below, m; = 0.60 kg is sliding down the incline with an initial speed of 2.5 m/s and ma is initially motionless. mslides through distance d = 1.50 m before colliding elastically with m2 -0.80 kg. m2 later comes to rest my moves frictionlessly, and the coefficient of kinetic friction between me and the incline is 0.70. (a) A diagram illustrating the initial “situation of interest" is given below. Draw diagrams illustrating all other relevant...
A stop block, s, prevents a crate from sliding down a 0 36.0° incline. (Figure 1) A tensile force F= (Fot) N acts on the crate parallel to the incline, where F 325 N/s If the coefficients of static and kinetic friction between the crate and the incline are 0.300 and 0.225 respectively, and the crate has a mass of 56.4 kg, how long will it take until the crate reaches a velocity of 2.07 m/s as it moves up...
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