Question

2. In each of the circuits shown, calculate the current through each resistor and potential difference across each resistor R-10 R=2022 {=20V R=2092 R=2012 R-1012 R=1092 -2014 {-10V R=150 &-10V R-1502 &;-10V R-1502 R=1002 20V R.=1092 R.=1092

Answer 1

Ans: lo2 202 152 As lov & zov batteries are Connected in series with some polarity facing each other, -lov M lour 20v Eea-20-10 = lov The circuit becomes, Reg= (301115) tlo le zor | 152 30x15 to = 45 - zor I lose 1A, Viorlov lor lov = 1 A Ilse = 3A, Vigalov Ilows = ZA, Viarter I zone=1/A, V220 V

204 20r I, Athu B By KVL in loop A BCFA, F Em My It Iz 1st +20-201 - 15 (I t Iz) lov - 10(I, + Iz) = 0 tu- E lor I 20-201, -15I, -15I2 - 10 I ,- 1012=0 20. – 45,- 25 I 2 =0 4= 91, +592 - 0 Now In doop F C DEF. 352- o gI, = 4 - 5 10(I + I2 +150It I2 + Ig(10) - 10 = 0 10 I, tlo Izt 15 lit ISI2 + loI2-1020 251, +35 I 2 = 10 4= 9 Its 51, +7 Iz=2 from ean & @ 48tit 2512-20 – 484, + 6352 =18 TAL A 1 3852=2

2oz 25 In loop ABCFA, - 201, + 20- 2501,+52) ost Limit-nut It c oor 15 - 201, +20-25I, - 25320 tu tlo Eu E lour love 45I +2512=20 I 2 = (4-9 ( 13 14 15 0 91, +512=4 - 91, +552=4-0 Now, In loop (FC DEFA), = 92-117 115 --25- 35 (I + I2)-10+10 I20 355, +3552-1otloszão - 8 A = 23 351, +45I2 =10 I, + 9 I 2 =2 -② from 0 2 0 81 I, + 4572=36 - 351, +4862 = 10 Voltage is the multiplication of current into that Resistance. 465,= 26 ) I, = 0