Question

For the circuit shown in the figure find the current through each resistor. For the circuit...

For the circuit shown in the figure find the curre

For the circuit shown in the figure find the current through each resistor.

For the circuit shown in the figure find the potential difference across each resistor.

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Answer #1
Concepts and reason

The concept required to solve the problem are equivalent resistance and ohm’s law.

The circuit diagram is given. Therefore, equivalent resistance of the circuit can be derived using combination of resistors. Further, as the voltage of the source is known, current through the circuit can be derived. Further, potential drop can across each resistor can be calculated using Ohm’s Law.

Fundamentals

Resistor is an electronic device that restricts passing of current through it. Resistors of different values can be connected in any combination in a circuit.

The equivalent resistance of the circuit is the total resistance to current in the circuit. The equivalent resistance for different combination can be divided into series combination of resistors and parallel combination of resistors.

Series combination:

In series combination, resistors are connected on the same branch. The current passing through series resistors is same.

Equivalent resistance for series combination is given by

R.y = R, + R2...+R,

Parallel combination:

In parallel combination, resistors are connected on different branch such that potential drop across them is same.

Equivalent resistance for parallel combination is given by

-=
-
+-..+-

Ohm’s law states that, “The electric current through a circuit is directly proportional to the voltage applied and the inversely proportional to the resistance of the circuit.”

(a)

As resistor612 and 1222
are parallel,

1
1
1
RAL 6*12
Rogi = 4

As Rand 422
are connected in series

Roq2 = Ragi +41
R.2 = 492+452
R.q2 = 812

As Rand 812
are parallel

1
1
1
Rog
1
Rope
1 1
8
Rog
Roz=4

As Rog = 4
and 2are connected in series

Recircuit = Roq3 +222
Rcircuit = 482 +222
Rcircuit = 622

Now, current through circuit

Rcircuit

Substitute 24 V for and for

I = 4A

As Rg and 22are in series

Current through both of them is same and equal to current through circuit

120 = 4A
103 = 4A

In , 8and Re=8
are connected parallel and have same resistance, current in them will be equally divided.

Therefore,

142 = 2A
180 = 2A

In , 492 and Roll
are in series, therefore, current though them is same and equal to 2A

140 = 2A
10q1 = 2A

In , 692 and 122
are connected parallel, will be divided amongst them according to their resistance. Since is half the value of 12, the current passing through it will be double.

Therefore,

V99-0= vy
vzx*= urly
‘OSIV
VĘCI=/
vzxz=

(b)

The voltage drops across each resistor can be given by

V=IR

Across resistor

V =(22)(4A)
V = 8V

Across resistor

V =(812)(2A)
V = 16V

Across resistor

V =(492)(2A)
V = 8V

Across resistor

V = (612)(1.33A)
V = 7.98V

As Across resistor

V = (1292)(0.665A)
V = 7.98V

Ans: Part a

The current through each resistor is given by

Resistor Current(A)
2Ω I 4
8Ω Ι 2
4Ω Τ
6ΩΙ 1.33
12Ω Ι 0.66
Βρα = 6Ω 4

Part b

The voltage-drop across each resistor is given by

Resistor Voltage Drop
2Ω
8Ω
16
4Ω
7.98
6Ω
12Ω
7.98

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